document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055662>Question 1055662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 260 feet and the length is 30 feet more than the width, what are the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670850 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W = Perimeter<BR>\n" );
document.write( "L = W+30 substitute for L in the equation above:<BR>\n" );
document.write( "2(W+30)+2W = 260<BR>\n" );
document.write( "2W+60+2W = 260<BR>\n" );
document.write( "4W = 200<BR>\n" );
document.write( "W = 50<BR>\n" );
document.write( "and<BR>\n" );
document.write( "L = 50+30 = 80 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );