document.write( "Question 1055662: If the perimeter of a rectangle is 260 feet and the length is 30 feet more than the width, what are the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #670848 by ikleyn(52787) $\"\"$ $\"About$

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\n" ); document.write( "If the perimeter of a rectangle is 260 feet and the length is 30 feet more than the width, what are the dimensions of the rectangle?
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document.write( "Let W be the width, then the length is W+30.\r\n" );
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document.write( "W + (W+30) + W + (W+30) = 260,\r\n" );
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document.write( "4W + 60 = 260,\r\n" );
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document.write( "4W = 260-60  --->  4W = 200  --->  W =  = 50.\r\n" );
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document.write( "Answer.  The wide is 50 ft.  The length is 50+30 = 80 ft.\r\n" );
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