document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055637>Question 1055637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a net of a solid shape . The two circular faces are congruent and each has a diameter of 7cm nd a hight of 25cm. Calculate the total surface are nd the volume of the solid shape formed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670821 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> net of a solid shape with two PARALLEL congruent circular faces. The shape has a height of 25 and each circular face has a diameter of 7.<BR>\n" );
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document.write( "Diameter 7, radius = D/2 = 7/2 = 3.5<BR>\n" );
document.write( "Height: 25<BR>\n" );
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document.write( "Area of the circle:<BR>\n" );
document.write( "Pir^2 = A<BR>\n" );
document.write( "Pi*3.5^2 = 38.48 this is the area of each of the circular faces, and we have 2 faces: 38.48*2 = 76.96<BR>\n" );
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document.write( ":Area of the cylinder:<BR>\n" );
document.write( "Perimeter of the faces:<BR>\n" );
document.write( "dPi = P<BR>\n" );
document.write( "7*Pi = 22<BR>\n" );
document.write( "Area of the side:<BR>\n" );
document.write( "22*25 = 550 Now add the area of the faces:<BR>\n" );
document.write( "550+76.95 = 626.96 you may have to round off to 627\r<BR>\n" );
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