document.write( "Question 1055498: A wind generator can charge 20 storage batteries in 24 h . After the generator has been charging for 6.0 h , another generator, which can charge the batteries in 36 h , is also connected to the batteries. How many additional hours are needed to charge the 20 batteries? \n" ); document.write( "
Algebra.Com's Answer #670704 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The rate of charging for the wind
\n" ); document.write( "generator is [ 1 pack ] / [ 24 hrs ]
\n" ); document.write( "( I can call the 20 storage batteries 1 pack
\n" ); document.write( "because the problem is only about the 20
\n" ); document.write( "batteries, never more & never less. )
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\n" ); document.write( "The fraction of charging after 6 hrs is:
\n" ); document.write( "\"+6%2A%28+1%2F24+%29+=+1%2F4+\"
\n" ); document.write( "There is \"+1+-+1%2F4+=+3%2F4+\" of the charging job
\n" ); document.write( "left to do
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "Now you have 2 generators charging the pack.
\n" ); document.write( "Add their rates of charging.
\n" ); document.write( "Let \"+t+\" = time to do the \"+3%2F4+\" of the charging job
\n" ); document.write( "\"+1%2F24+%2B+1%2F36+=+%28%283%2F4%29%29%2Ft+\"
\n" ); document.write( "Multiply both sides by \"+72t+\"
\n" ); document.write( "\"+3t+%2B+2t+=+3%2A18+\"
\n" ); document.write( "\"+5t+=+54+\"
\n" ); document.write( "\"+t+=+10.8+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "10.8 additional hours are needed
\n" ); document.write( "to charge the 20 batteries
\n" ); document.write( "-------------------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+1%2F24+%2B+1%2F36+=+%28%283%2F4%29%29%2Ft+\"
\n" ); document.write( "\"+1%2F24+%2B+1%2F36+=+%28%283%2F4%29%29%2F10.8+\"
\n" ); document.write( "\"+.0416667+%2B+.027777+=+.069444+\"
\n" ); document.write( "\"+.0694437+=+.069444+\"
\n" ); document.write( "error due to rounding off, I think
\n" ); document.write( "OK\r
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