document.write( "Question 1055447: Nearly one-half of Americans aged 25 to 29 are unmarried. How large a sample is necessary to estimate the true proportion of unmarried Americans in this age group within 2 1/2 percentage points with 90% confidence?
\n" ); document.write( "Thanks! \n" ); document.write( "
Algebra.Com's Answer #670699 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
ME = \"z%2Asqrt%28%28p%281-p%29%29%2Fn%29\"
\n" ); document.write( "0r
\n" ); document.write( "n = \"%28z%2FME%29%5E2+%28p%281-p%29%29%29\"
\n" ); document.write( "n = \"%281.645%2F.025%29%5E2+%28.5%28.5%29%29\" round Up to nearest whole number
\n" ); document.write( "|
\n" ); document.write( "|
\n" ); document.write( " = CI z = value
\n" ); document.write( "90% z =1.645
\n" ); document.write( "92% z = 1.751
\n" ); document.write( "95% z = 1.96
\n" ); document.write( "98% z = 2.326
\n" ); document.write( "99% z = 2.576
\n" ); document.write( " \n" ); document.write( "
\n" );