document.write( "Question 1055418: How many four-digit odd numbers can be formed from the digits
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document.write( "1, 2, 4, 5, 6, and 9 if each digit can only be used once? \n" );
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Algebra.Com's Answer #670648 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! How many four-digit odd numbers can be formed from the digits \n" ); document.write( "1, 2, 4, 5, 6, and 9 if each digit can only be used once? \n" ); document.write( " \r\n" ); document.write( "Rule for this type problem:\r\n" ); document.write( "\r\n" ); document.write( "Choose the most restrictive thing(s) first!\r\n" ); document.write( "\r\n" ); document.write( "Since the number must be odd, the last digit must\r\n" ); document.write( "be odd.\r\n" ); document.write( "\r\n" ); document.write( "So the last digit is the most restrictive thing to choose.\r\n" ); document.write( "\r\n" ); document.write( "So we choose the last digit first:\r\n" ); document.write( "\r\n" ); document.write( "We can choose the last, or 4th, digit 3 ways, 1, 5, or 9.\r\n" ); document.write( "We can then choose the 1st digit 5 ways\r\n" ); document.write( "(as any of the remaining 5 digits).\r\n" ); document.write( "We can then choose the 2nd digit 4 ways\r\n" ); document.write( "(as any of the remaining 4 digits).\r\n" ); document.write( "We can then choose the 3rd digit 3 ways\r\n" ); document.write( "(as any of the remaining 3 digits).\r\n" ); document.write( "\r\n" ); document.write( "That's 3×5×4×3 = 180 ways.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |