document.write( "Question 1055386: I'm not sure how to do this question. Could you please help?:
\n" ); document.write( "Diagram: http://imgur.com/a/7ucNQ
\n" ); document.write( "This rectangle is a golden rectangle.
\n" ); document.write( "– ABEF is a square.
\n" ); document.write( "– Rectangle BCDE is similar to rectangle ACDF.
\n" ); document.write( "a) Show that a/1= 1/(a-1)
\n" ); document.write( "b) Find the exact value of a (which will give you the golden ratio) by completing the square.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advanced :)
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Algebra.Com's Answer #670630 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Given the similarity between the two rectangles, that is already the justification for \"a%2Fy=y%2F%28a-1%29\". The reason is, their similarity is given. The equation, replacing your \"1\" with a \"y\" is simply the proportion for comparing the corresponding rectangular parts.\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"a%28a-1%29=y%5E2\"
\n" ); document.write( "\"a%5E2-a-y%5E2=0\"
\n" ); document.write( "skipping trying to complete square;
\n" ); document.write( "\"a=%281%2B-+sqrt%281%2B4y%5E2%29%29%2F2\", and probably want the PLUS form.
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