document.write( "Question 1055412: Solve: \"+%285-b%29%2Fb+%2B+3%2F4+=+7%2Fb+\"\r
\n" ); document.write( "\n" ); document.write( "So far, I applied the LCD method to this. My LCD is 4b which I multiplied to the equation to get 4(5-b) + 3b = 7(4) which equals 20-4b+3b=28. From that point I'm unsure if you do set it to zero or set it as -4b+3b = 28-20 but it doesn't say solve for b. Or if the LCD method is even applied at all.
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Algebra.Com's Answer #670620 by ikleyn(52805)\"\" \"About 
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\n" ); document.write( "Solve: \"+%285-b%29%2Fb+%2B+3%2F4+=+7%2Fb+\"
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document.write( "Multiply by LCD = 4b both sides. You will get\r\n" );
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document.write( "4*(5-b) + 3b = 7*4,\r\n" );
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document.write( "20 - 4b + 3b = 28,\r\n" );
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document.write( "-4b + 3b = 28 - 20,\r\n" );
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document.write( "-b = 8,\r\n" );
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document.write( "b = -8.\r\n" );
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document.write( "Answer.  b = -8.\r\n" );
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