document.write( "Question 1055367: Fifteen litres of fuel containing 3.2% oil is available for a certain two-cycle engine. This fuel is to be used for another engine requiring a 5.5% oil mixture. How many litres of oil must be added? \n" ); document.write( "
Algebra.Com's Answer #670607 by ikleyn(52776)\"\" \"About 
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\n" ); document.write( "Fifteen litres of fuel containing 3.2% oil is available for a certain two-cycle engine.
\n" ); document.write( "This fuel is to be used for another engine requiring a 5.5% oil mixture. How many litres of oil must be added?
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document.write( "The basic equation is \r\n" );
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document.write( "\"%2815%2A0.032+%2B+v%29%2F%2815+%2B+v%29\" = 0.055.   (1)\r\n" );
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document.write( "To solve it, multiply both sides by (15 + v). You will get\r\n" );
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document.write( "15*0.032 + v = 0.055*(15+v),\r\n" );
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document.write( "0.48 + v = 0.825 + 0.055v,\r\n" );
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document.write( "v - 0.055v = 0.825-0.48,\r\n" );
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document.write( "0.945v = 0.345  --->  v = \"0.345%2F0.945\" = 0.365.\r\n" );
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document.write( "Answer.  0.365 liters of oil must be added.\r\n" );
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