document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055348>Question 1055348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> &#8736;A and &#8736;B are supplementary angles. If m&#8736;A=(x+23)&#8728; and m&#8736;B=(2x+13)&#8728;, then find the measure of &#8736;A.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670575 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  &#8736;A and &#8736;B are supplementary angles. If m&#8736;A=(x+23)&#8728; and m&#8736;B=(2x+13)&#8728;, then find the measure of &#8736;A. <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x+23 + 2x+13 = 180<BR>\n" );
document.write( "3x + 36 = 180<BR>\n" );
document.write( "x + 12 = 60<BR>\n" );
document.write( "x = 48<BR>\n" );
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document.write( "A = x+23 = 48 + 23 = 71 degrees<BR>\n" );
document.write( "B = 2x+13 = 2*48 + 13 = 96+13 = 109 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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