document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055347>Question 1055347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of brass containing  63% copper must be melted with  1100 of brass containing   72% copper to produce a new brass containing  67%  copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670574 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How many kilograms of brass containing 63% copper must be melted with 1100 of brass containing 72% copper to produce a new brass containing 67% copper? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "cop + cop = cop<BR>\n" );
document.write( "0.63x + 0.72*1100 = 0.67(x+1100)<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "63x + 72*1100 = 67x + 67*1100<BR>\n" );
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document.write( "4x = 5*1100<BR>\n" );
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document.write( "x =  5*275<BR>\n" );
document.write( "x = 1375 units (amt. of 63% brass needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------- </SPAN>\n" );
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