document.write( "Question 1055344: Find a polynomial function of degree 3 with the given numbers as zeros.
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document.write( "2,i, -i\r
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document.write( "This is what I tried:
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document.write( "F(x)=(x-2)(x+i)(x-i)
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document.write( "I factored(x+i)(x-i) and got x^2-1
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document.write( "After that I factored (x^2-1)(x-2)
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document.write( "I got x^3-2x^2-x+2\r
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document.write( "I'm not exactly sure if I did that correctly.
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document.write( "
Algebra.Com's Answer #670573 by Boreal(15235) You can put this solution on YOUR website! There are three real roots in the graph \n" ); document.write( " \n" ); document.write( "You want (x^2+1), because (x+i)(x-i)=x^2-i^2=x^2-(-1)=x^2+1 \n" ); document.write( "Now expand (x^2+1)(x-2) \n" ); document.write( "x^3-2x^2+x-2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |