document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055339>Question 1055339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain bronze alloy containing 4%  tin is to be added to 350kg  of bronze containing  18% tin to produce a new bronze containing 15%  tin. How many kilograms of the 4% bronze alloy are required? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670570 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A certain bronze alloy containing 4% tin is to be added to 350kg of bronze containing 18% tin to produce a new bronze containing 15% tin. How many kilograms of the 4% bronze alloy are required?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "tin + tin = tin<BR>\n" );
document.write( "0.04x + 0.18*350 = 0.14(x+350)<BR>\n" );
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document.write( "4x + 18*350 = 14x + 14*350<BR>\n" );
document.write( "10x = 4*350<BR>\n" );
document.write( "x = 4*35<BR>\n" );
document.write( "x = 140 kg (amt of bronze alloy needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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