document.write( "Question 1055223: The revenue function for a new plasma television is given by R(p) = 900p-0.1p^2
\n" ); document.write( " What price, p, should be charged to maximize revenue? What is the maximum revenue?
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Algebra.Com's Answer #670489 by Fombitz(32388) $\"\"$ $\"About$

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Convert the revenue function to vertex form,
\n" ); document.write( " $\"R%28p%29=-0.1p%5E2%2B900p\"$
\n" ); document.write( " $\"R%28p%29=-0.1%28p%5E2-9000p%29\"$
\n" ); document.write( " $\"R%28p%29=-0.1%28p%5E2-9000p%2B4500%5E2%29%2B0.1%284500%29%5E2\"$
\n" ); document.write( " $\"R%28p%29=-0.1%28p-4500%29%5E2%2B2025000\"$
\n" ); document.write( "So the $\"R%5Bmax%5D=2025000\"$ occurs when $\"p=4500\"$ . \n" ); document.write( "

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