document.write( "Question 1055238: Nicolas mixes three solutions of acid with concentrations of 10%, 15%, and 5%. He wants to make 30 L of a mixture that is 12% acid and he uses four times as much of the 15% solution as the 5% solution. How much each of the three solutions must he use? \n" ); document.write( "
Algebra.Com's Answer #670449 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Three-part mixture but you can turn this into something that looks like a two-part mixture problem.\r
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document.write( "VOLUME     CONCENTRATION\r\n" );
document.write( "x            5%\r\n" );
document.write( "y           10%\r\n" );
document.write( "z           15%\r\n" );
document.write( "\r\n" );
document.write( "\"z%2Fx=4\"\r\n" );
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\n" ); document.write( "Already an equation is identified.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28%285x%2B10y%2B15z%29%2F30=12%2Cx%2By%2Bz=30%29\"
\n" ); document.write( "and again, you know one already found equation, useful as \"z=4x\".\r
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\n" ); document.write( "\n" ); document.write( "\"system%28%285x%2B10y%2B15%284x%29%29%2F30=12%2Cx%2By%2B4x=30%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%2865x%2B10y=360%2C5x%2By=30%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%2812x%2B2y=72%2C5x%2By=30%29\"
\n" ); document.write( "If you think carefully for a few seconds, you can continue this partly through Elimination Method.\r
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\n" ); document.write( "\n" ); document.write( "( x=6 )
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