document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055210>Question 1055210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of x, correct to 1 decimal place, in this diagram if the area is to be 20 square units.\r<BR>\n" );
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document.write( "Diagram: http://imgur.com/a/d2Kdt\r<BR>\n" );
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document.write( "Here is my working, the answer I got is different from the answer in the book which is 1.6 \r<BR>\n" );
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document.write( "x(x+10)+ 1/2(pi x^2) =20<BR>\n" );
document.write( "x^2 +10x + 1/2(pi x^2)= 20<BR>\n" );
document.write( "2x^2+20x+pi x^2=40<BR>\n" );
document.write( "(2+pi)x^2+20x-40=0<BR>\n" );
document.write( "since x>0, x=1.455  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670413 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First step is wrong.<BR>\n" );
document.write( "Idea of sum of the two area parts is conceptually correct.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28x%28x%2B10%29%2B%28pi%2F2%29%28x%2F2%29%5E2=20%29 ALIGN=MIDDLE  ALT=\"highlight_green%28x%28x%2B10%29%2B%28pi%2F2%29%28x%2F2%29%5E2=20%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "NOW you should be able to solve and find a better result. </SPAN>\n" );
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