document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92191>Question 92191</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977258/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> please show me how to do this problem! If y varies directly with x, and y = 10 when x = 15, find y when x = 6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67041 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if y varies directly with x, then they are on opposite sides of an equation with a constant of variation (fudge factor)\r<BR>\n" );
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document.write( "use the given values to find the constant, then use the constant to find other values\r<BR>\n" );
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document.write( "y=kx ... 10=k(15) ... 10/15=k ... k=2/3 ... y=(2/3)(6) ... y=4 </SPAN>\n" );
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