document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1055146>Question 1055146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The velocity of the plane in still air is 125 kph. The velocity of the wind due east is 25 kph. If the plane travels east and returns back to its base again after 4 hours, what distance does the plane travels due east? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670341 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The velocity of the plane in still air is 125 kph. The velocity of the wind due east is 25 kph. If the plane travels east and returns back to its base again after 4 hours, what distance does the plane travels due east?<BR>\n" );
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document.write( "t = hours downwind<BR>\n" );
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document.write( "d = 150*t - downwind<BR>\n" );
document.write( "d = 100*(4-t) - upwind<BR>\n" );
document.write( "150t = 400 - 100t<BR>\n" );
document.write( "t = 400/250 = 1.6 hours flying downwind<BR>\n" );
document.write( "d = 150*1.6 = 240 kms\r<BR>\n" );
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