document.write( "Question 1055098: \"James invested some money at 10% interest. James also invested $90 more than 3 times that amount at 8%. How much is invested at each rate if James receives $798.38 in interest after one year?\" \n" ); document.write( "
Algebra.Com's Answer #670338 by tehreem(2)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let the investment be $x \r \n" ); document.write( "\n" ); document.write( "$x at 10% interest is x(1+0.1) = 1.1x\r \n" ); document.write( "\n" ); document.write( "$(90+3x) at 8% interest = 1.08 (90 +3x) = 97.2 + 3.24x \r \n" ); document.write( "\n" ); document.write( "if the total amount he receives by the end of the year is 798.38 , then:\r \n" ); document.write( "\n" ); document.write( "1.1x + 97.2 + 3.24x = 798.38 \n" ); document.write( "4.34x = 798.38 - 97.2 \n" ); document.write( "4.34x = 701.18\r \n" ); document.write( "\n" ); document.write( "x = 162 \n" ); document.write( " \n" ); document.write( "(now substitute the value of x ) \n" ); document.write( "1.1 x 162= $178 at 10 % interest rate \n" ); document.write( "97.2 + 3.24(162) = $622 at 8% interest rate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |