document.write( "Question 1055125: A cyclist and a jogger start from a town at the same time and head for a destination 12 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 1.2 h before the jogger. Find the rate of the cyclist. \n" ); document.write( "

Algebra.Com's Answer #670322 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "A cyclist and a jogger start from a town at the same time and head for a destination 12 mi away.
\n" ); document.write( "The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 1.2 h before the jogger. Find the rate of the cyclist.
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document.write( "One equation is\r\n" );
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document.write( " = 1.2,   (1)\r\n" );
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document.write( "where j is the jogger's rate, c is the cyclist's rate.\r\n" );
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document.write( "The other equation is \r\n" );
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document.write( "c = 2j.                    (2)\r\n" );
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document.write( "Substitute (2) into (1). You will get\r\n" );
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document.write( " = 1.2.\r\n" );
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document.write( "Multiply both sides by (2j). You will get\r\n" );
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document.write( "24 - 12 = 2.4j  --->  12 = 2.4j  --->  j = 5 mph.\r\n" );
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document.write( "Then c = 10 mph.\r\n" );
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