document.write( "Question 1055127: A commercial jet travels 1500 mi in the same amount of time it takes a corporate jet to travel 1290 mi. The rate of the commercial jet is 70 mph greater than the rate of the corporate jet. Find the rate of each jet. \n" ); document.write( "
Algebra.Com's Answer #670317 by ikleyn(52856)\"\" \"About 
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\n" ); document.write( "A commercial jet travels 1500 mi in the same amount of time it takes a corporate jet to travel 1290 mi.
\n" ); document.write( "The rate of the commercial jet is 70 mph greater than the rate of the corporate jet. Find the rate of each jet.
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document.write( "Your equation is\r\n" );
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document.write( "\"1500%2F%28s%2B70%29\" = \"1290%2Fs\"\r\n" );
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document.write( "where s is the rate of the slower (=corporate) jet (in mph).\r\n" );
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document.write( "Multiply both sides by s*(s+70).\r\n" );
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document.write( "The rest is just arithmetic.\r\n" );
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