document.write( "Question 1055034: use a normal approximation to find the probability of the indicated scores, assume that n=100 and p=0.22\r
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document.write( "probability that x is at least 25\r
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document.write( "probability that x is exactly 19 \n" );
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Algebra.Com's Answer #670302 by stanbon(75887) ![]() You can put this solution on YOUR website! use a normal approximation to find the probability of the indicated scores, assume that n=100 and p=0.22 \n" ); document.write( "probability that x is at least 25 \n" ); document.write( "--- \n" ); document.write( "mean = n*p = 22 \n" ); document.write( "std = sqrt(22*0.78) = 4.14 \n" ); document.write( "-------------------------------- \n" ); document.write( "P(x >= 25) ~ P(x >= 24.5) \n" ); document.write( "z(24.5) = (24.5-22)/4.14 = 0.60 \n" ); document.write( "--------- \n" ); document.write( "p(x >= 25) = P(z >= 0.6) = normalcdf(0.6,100) = 0.2743 \n" ); document.write( "-------------------------------------------------------------- \n" ); document.write( "probability that x is exactly 19 \n" ); document.write( "P(x = 19) ~ P(18.5 <= x <= 19.5) \n" ); document.write( "z(18.5) = (18.5-22)/4.14 = -0.85 \n" ); document.write( "z(19.5) = (19.5-22)/4.14 = 0.60 \n" ); document.write( "---- \n" ); document.write( "P(x = 19) ~ P(-0.85<= z <= 0.6) = normalcdf(-0.85,0.6) = 0.5281 \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------- \n" ); document.write( " \n" ); document.write( " |