document.write( "Question 1055026: the waiting time x at a certain bank is approximately normally distributed with a mean of 3.7 minutes and a standard deviation of 1.4 minutes. \r
\n" ); document.write( "\n" ); document.write( "find the 75th percentile for waiting times at this bank.
\n" ); document.write( "Find the probability that a customer has to wait more than 6 minutes.
\n" ); document.write( "I believe the probability is 0.05 or 5 percent for this one but I'm not sure.
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Algebra.Com's Answer #670220 by ewatrrr(24785)\"\" \"About 
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mean of 3.7 minutes and a standard deviation of 1.4 minutes
\n" ); document.write( "\"z+=blue+%28x+-+mu%29%2Fblue%28sigma%29\"
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\n" ); document.write( "\"blue%28sigma%29%2Az+%2B+mu=+blue+%28x%29\"
\n" ); document.write( "the 75th percentile for waiting times at this bank: z = invNorm(.75) = .6745
\n" ); document.write( "\"blue%281.4%29%2A.6745+%2B+3.7=+blue+%284.6436%29\" x = 4.7 always round Up for these
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\n" ); document.write( "P(x > 6) = P(\"z+=blue+%286.0+-+3.7%29%2Fblue%281.4%29\" )
\n" ); document.write( "Find z and then find P(z > value found) = normalcdf(value found, 100) 100 a placeholder
\n" ); document.write( "z = 1.6429
\n" ); document.write( "P(z > 1.6429) = normalcdf(1.6429, 100) = .05 0r 5%
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