document.write( "Question 1055026: the waiting time x at a certain bank is approximately normally distributed with a mean of 3.7 minutes and a standard deviation of 1.4 minutes. \r
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document.write( "find the 75th percentile for waiting times at this bank.
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document.write( "Find the probability that a customer has to wait more than 6 minutes.
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document.write( "I believe the probability is 0.05 or 5 percent for this one but I'm not sure. \n" );
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Algebra.Com's Answer #670220 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean of 3.7 minutes and a standard deviation of 1.4 minutes \n" ); document.write( " \n" ); document.write( "0r \n" ); document.write( " \n" ); document.write( "the 75th percentile for waiting times at this bank: z = invNorm(.75) = .6745 \n" ); document.write( " \n" ); document.write( "| \n" ); document.write( "P(x > 6) = P( \n" ); document.write( "Find z and then find P(z > value found) = normalcdf(value found, 100) 100 a placeholder \n" ); document.write( "z = 1.6429 \n" ); document.write( "P(z > 1.6429) = normalcdf(1.6429, 100) = .05 0r 5% \n" ); document.write( " \n" ); document.write( " |