document.write( "Question 1054963: How to solve Write the augmented matrix as a system of equations in TI-84 plus\r
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document.write( "z-d-b=200
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document.write( "z +2b=250
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document.write( " b=150 \n" );
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Algebra.Com's Answer #670182 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! z-d-b=200 \n" ); document.write( "z +2b=250 \n" ); document.write( "b=150 \n" ); document.write( " \r\n" ); document.write( "Line up like letters\r\n" ); document.write( "Line up the equal sign\r\n" ); document.write( "Line up the numbers on the right sides:\r\n" ); document.write( "\r\n" ); document.write( "z - d - b = 200\r\n" ); document.write( "z + 2b = 250\r\n" ); document.write( " b = 150\r\n" ); document.write( "\r\n" ); document.write( "Put 1 coefficients which are usually left understood:\r\n" ); document.write( "\r\n" ); document.write( "1z - 1d - 1b = 200\r\n" ); document.write( "1z + 2b = 250\r\n" ); document.write( " 1b = 150\r\n" ); document.write( "\r\n" ); document.write( "Put in place holder \"+ 0 times the letter\" terms for \r\n" ); document.write( "the missing letters in the second and third \r\n" ); document.write( "equations:\r\n" ); document.write( "\r\n" ); document.write( "1z - 1d - 1b = 200\r\n" ); document.write( "1z + 0d + 2b = 250\r\n" ); document.write( "0z + 0d + 1b = 150\r\n" ); document.write( "\r\n" ); document.write( "That can be abbreviated by a matrix by erasing\r\n" ); document.write( "all the letters and putting the - signs close to the \r\n" ); document.write( "numbers, and erasing the + signs. Erase the = signs.\r\n" ); document.write( "\r\n" ); document.write( "[1 -1 -1 200]\r\n" ); document.write( "[1 0 2 250]\r\n" ); document.write( "[0 0 1 150]\r\n" ); document.write( "\r\n" ); document.write( "Press 2ND MATRIX (the x-1 key).\r\n" ); document.write( "Highlight EDIT.\r\n" ); document.write( "Press ENTER.\r\n" ); document.write( "\r\n" ); document.write( "Make it read MATRIX[A] 3 x 4\r\n" ); document.write( "\r\n" ); document.write( "type in all the numbers in the above matrix. The\r\n" ); document.write( "brackets \"[\" and \"]\" are already there.\r\n" ); document.write( "\r\n" ); document.write( "Press 2ND QUIT (the MODE key)\r\n" ); document.write( "Press CLEAR\r\n" ); document.write( "\r\n" ); document.write( "Press 2ND MATRIX (the x-1 key).\r\n" ); document.write( "\r\n" ); document.write( "Highlight MATH\r\n" ); document.write( "Scroll with arrow to B:rref(\r\n" ); document.write( "Press ENTER\r\n" ); document.write( "\r\n" ); document.write( "See rref( followed by blinking cursor.\r\n" ); document.write( "\r\n" ); document.write( "Press 2ND MATRIX (the x-1 key)\r\n" ); document.write( "\r\n" ); document.write( "Press ENTER\r\n" ); document.write( "\r\n" ); document.write( "See rref([A]\r\n" ); document.write( "\r\n" ); document.write( "Press ) then ENTER\r\n" ); document.write( "\r\n" ); document.write( "Screen should read\r\n" ); document.write( "\r\n" ); document.write( "rref([A])\r\n" ); document.write( " [[1 0 0 -50 ]\r\n" ); document.write( " [0 1 0 -400] \r\n" ); document.write( " [0 0 1 150 ]]\r\n" ); document.write( "\r\n" ); document.write( "This means\r\n" ); document.write( "\r\n" ); document.write( "1x + 0y + 0z = -50\r\n" ); document.write( "0x + 1y + 0z = -400\r\n" ); document.write( "0x + 0y + 1z = 150\r\n" ); document.write( "\r\n" ); document.write( "or erasing the placeholder terms and the 1\r\n" ); document.write( "coefficients:\r\n" ); document.write( "\r\n" ); document.write( " x = -50\r\n" ); document.write( " y = -400\r\n" ); document.write( " z = 150\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |