document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054931>Question 1054931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the ages of afraz and Sam is 33 years. In two years, 3 times Afraz's age will be one year less than 4 times sams age. How old is each now?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670153 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A+S=33<BR>\n" );
document.write( "3(A+2)+1=4(S+2). which means that if I add 1 to 3 times A's age in two years, I get 4 times S. age in 2 years.<BR>\n" );
document.write( "3A+7=4S+8<BR>\n" );
document.write( "But A=33-S<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( "99-3S+7=4S+8<BR>\n" );
document.write( "98=7S<BR>\n" );
document.write( "S=14 now<BR>\n" );
document.write( "A=19 now<BR>\n" );
document.write( "In two years A will be 21 and 3 times that is 63.  That is 1 year less than 4 times S. age, which is 64.<BR>\n" );
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