document.write( "Question 1054904: (a) i. Show that if a + a -1 = 10/3 then 3a2 – 10a + 3 = 0
\n" ); document.write( " ii. Hence find { x : 3x + 3–x = 10/3}\r
\n" ); document.write( "\n" ); document.write( " in i.: a -1 is suppose to be a inverse
\n" ); document.write( " and 3a2 is actually 3a squared
\n" ); document.write( "in ii.: 3x is actually 3 to the power x
\n" ); document.write( " and 3-x is actually 3 to the power negative x
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Algebra.Com's Answer #670151 by ikleyn(52847)\"\" \"About 
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\n" ); document.write( "Do you know WHAT?\r
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\n" ); document.write( "\n" ); document.write( "Better learn how to write your equations correctly.\r
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