document.write( "Question 19879: The length of a rectangular garden is 10 feet longer than its width. If the garden's perimeter is 184 feet, what is the area of the garden in square feet?
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Algebra.Com's Answer #67015 by zerosignal(28)\"\" \"About 
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Given: length is 10 ft longer than its width, perimeter is 184 ft.\r
\n" ); document.write( "\n" ); document.write( "Let x = width (a)
\n" ); document.write( "Let x+10 = length (b)\r
\n" ); document.write( "\n" ); document.write( "\"perimeter+=+2a+%2B+2b\"
\n" ); document.write( "\"184+=+2x+%2B+2%28x%2B10%29\"
\n" ); document.write( "\"184+=+2x+%2B+2x+%2B+20\"
\n" ); document.write( "\"184+=+4x+%2B+20\"
\n" ); document.write( "\"164+=+4x\"
\n" ); document.write( "\"41+=+x\"\r
\n" ); document.write( "\n" ); document.write( "therefore, the width of the garden is 41 feet, and the length is 41+10 = 51 feet.\r
\n" ); document.write( "\n" ); document.write( "Area of a rectangle is A = a*b\r
\n" ); document.write( "\n" ); document.write( "\"a+=+41%2A51\"
\n" ); document.write( "\"a+=+2091\"\"ft%5E2\"
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