document.write( "Question 1054941: The shrinkage in length of a certain brand of blue jeans is normally distributed with a mean of 1.1000000000000001 inch and a standard deviation of 0.2 inch. What percent of this brand of jeans will shrink more than 1.5 inches?
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document.write( "The possible answers to this question were 2.279..., 0.433, 1.3, 1.779... \n" );
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Algebra.Com's Answer #670146 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean of 1.10 inch and a standard deviation of 0.2 inch \n" ); document.write( "p(x > 1.5) = p(z > (1.5-1.10)/.2) = p(z > .4/.2) = normalcdf(2, 100) 100 a placeholder \n" ); document.write( "| Using Caculator.............................. \n" ); document.write( "normalcdf(2, 100)= .0228 0r 2.28% \n" ); document.write( " \n" ); document.write( " |