document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054919>Question 1054919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40 liters of a 35% solution? Also please include a chart if u could.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670114 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = the number of liters of the 20% solution.\r<BR>\n" );
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document.write( "let y = the number of liters of the 60% solution.\r<BR>\n" );
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document.write( "you want x + y to be equal to 40 liters.\r<BR>\n" );
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document.write( "x is the number of liters total in the first solution.<BR>\n" );
document.write( "y is the number of liters total in the second solution.\r<BR>\n" );
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document.write( "you want .2 * x + .6 * y to be equal to .35 * 40\r<BR>\n" );
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document.write( ".2 * x is the number of liters of acid in the first solution.<BR>\n" );
document.write( ".6 * y is the number of liters of acid in the second solution.<BR>\n" );
document.write( ".35 * 40 is the number of liters of acid in the final solution.\r<BR>\n" );
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document.write( "you have two equations that need to be solved simultaneously.\r<BR>\n" );
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document.write( "they are:\r<BR>\n" );
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document.write( "x + y = 40<BR>\n" );
document.write( ".2x + .6y = .35*40\r<BR>\n" );
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document.write( "simplify these equations to get:\r<BR>\n" );
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document.write( "x + y = 40<BR>\n" );
document.write( ".2x + .6y = 14\r<BR>\n" );
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document.write( "you can solve by substitution or by elimination or by graphing.<BR>\n" );
document.write( "i will solve this one by graphing.<BR>\n" );
document.write( "this means to graph both equations and find the intersection.\r<BR>\n" );
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document.write( "the graph looks like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2016/102903.jpg\" alt=\"$$$\"\r<BR>\n" );
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document.write( "the graph says the intersection is at the coordinate point of (25,15).\r<BR>\n" );
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document.write( "this means that x = 25 and y = 15.\r<BR>\n" );
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document.write( "x is the number of liters of the 20% solution.<BR>\n" );
document.write( "y is the number of liters of the 60% solution.\r<BR>\n" );
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document.write( "the formula of .2x + .6y = 14 becomes .2 * 25 + .6 * 15 = 14.<BR>\n" );
document.write( "simplify this equation to get 14 = 14.<BR>\n" );
document.write( "this confirms the solution is good.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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