document.write( "Question 1054900: two water taps together can fill a tank in 9 3/8 hours.the tap of larger diamer taker 10 hours less than the smaller one to fill the tank separately find the time in which each tap can separately fill the tank. \n" ); document.write( "

Algebra.Com's Answer #670113 by jorel555(1290) $\"\"$ $\"About$

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Let n be the larger tap. Then the smaller tap would be n+10. So:
\n" ); document.write( "1/n+1/(n+10)=1/(75/8)=8/75
\n" ); document.write( "75(n+10)+75n=8n²+80n
\n" ); document.write( "8n²-70n-750=0
\n" ); document.write( "4n²-35n-375=0
\n" ); document.write( "(4n+25)(n-15)=0
\n" ); document.write( "n=15,-25/4
\n" ); document.write( "Throwing out the negative result, we get the bigger tap filling the tank in 15 hours, and the smaller tap in 25 hrs.. ☺☺☺☺ \n" ); document.write( "

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