document.write( "Question 1054919: How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40 liters of a 35% solution? Also please include a chart if u could. \n" ); document.write( "
Algebra.Com's Answer #670111 by jorel555(1290)\"\" \"About 
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Let n be the amount of 60% solution. Then:
\n" ); document.write( ".6n+.2(40-n)=.35(40)
\n" ); document.write( ".4n=6
\n" ); document.write( "n=15
\n" ); document.write( "You need 15 liters of 60% solution and 25 liters of 20% solution for your desired mixture. ☺☺☺☺
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