document.write( "Question 1054919: How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40 liters of a 35% solution? Also please include a chart if u could. \n" ); document.write( "
Algebra.Com's Answer #670111 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the amount of 60% solution. Then: \n" ); document.write( ".6n+.2(40-n)=.35(40) \n" ); document.write( ".4n=6 \n" ); document.write( "n=15 \n" ); document.write( "You need 15 liters of 60% solution and 25 liters of 20% solution for your desired mixture. ☺☺☺☺ \n" ); document.write( " |