document.write( "Question 1054896: A firm submits tenders for two different contracts. The tenders will be assessed independently. The probability that the first tender will be accepted is70%. And the probability that the second tender will be successful is 40% . Q1 What's the probability that only first will be successful ? Q2 what's the probailty that the first or the second will be successful ? ........ My solution for Q1 is 1-p(1)=0.3 and my solution for Q2 is 0.7+0.4=1.1 ......Could you please tell me if I'm right or wrong. Thank you \n" ); document.write( "
Algebra.Com's Answer #670102 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! P(1st one Successful) = .70 \n" ); document.write( "P(2nd one Successful) = .40 \n" ); document.write( "| \n" ); document.write( "P(1st AND not 2nd) = .70(.60) \n" ); document.write( "P(1st Or 2nd) = .70 + .40 - both(.70*.40) \n" ); document.write( " |