document.write( "Question 1054892: Given \"+n%28x%29=x%5E2-9+\"
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Algebra.Com's Answer #670101 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Given:  n(x) = x2-9 \r\n" );
document.write( "        m(x) = x+3 \r\n" );
document.write( "        p(x) = √x+1\r\n" );
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document.write( "Use the functions to find:\r\n" );
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document.write( "a. (n-m)(-6)\r\n" );
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document.write( "First we find (n-m)(x)\r\n" );
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document.write( "(n-m)(x) = \r\n" );
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document.write( "(n-m)(x) = n(x) - m(x) = \r\n" );
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document.write( "(n-m)(x) = (x2-9) - (x+3) = \r\n" );
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document.write( "(n-m)(x) = x2-9-x-3 = \r\n" );
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document.write( "(n-m)(x) = x2-x-12 \r\n" );
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document.write( "Now substitute (-6) for x\r\n" );
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document.write( "(n-m)(-6) = (-6)2-(-6)-12\r\n" );
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document.write( "(n-m)(-6) = 36+6-12\r\n" );
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document.write( "(n-m)(-6) = 30\r\n" );
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document.write( "-------------------------\r\n" );
document.write( "b.  (n•p)(0) \r\n" );
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document.write( "First we find (n•p)(x)\r\n" );
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document.write( "(n•p)(x) = n(x)•p(x)\r\n" );
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document.write( "(n•p)(x) = (x2-9)•(√x+1)\r\n" );
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document.write( "Now substitute 0 for x\r\n" );
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document.write( "(n•p)(0) = (02-9)•√0+1\r\n" );
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document.write( "(n•p)(0) = (0-9)•√1\r\n" );
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document.write( "(n•p)(0) = (-9)•1\r\n" );
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document.write( "(n•p)(0) = -9\r\n" );
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document.write( "c. \"%28p%2Fm%29\"(0) \r\n" );
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document.write( "First we find \"%28p%2Fm%29\"(x) \r\n" );
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document.write( "\"%28p%2Fm%29\"(x) = \"%22p%28x%29%22%2F%22m%28x%29%22\"\r\n" );
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document.write( "\"%28p%2Fm%29\"(x) = \"sqrt%28x%2B1%29%2F%28x%2B3%29\"\r\n" );
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document.write( "Now substitute 0 for x\r\n" );
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document.write( "\"%28p%2Fm%29\"(0) = \"sqrt%280%2B1%29%2F%280%2B3%29\"\r\n" );
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document.write( "\"%28p%2Fm%29\"(0) = \"sqrt%281%29%2F3\"\r\n" );
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document.write( "\"%28p%2Fm%29\"(0) = \"1%2F3\"\r\n" );
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document.write( "Edwin
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