document.write( "Question 1054884: Of 110 clock radios sold recently in a department store, 60 had FM circuitry, and 80 had AM circuitry. How many could receive FM transmission only?
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document.write( "10
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document.write( "60
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document.write( "20
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document.write( "50
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document.write( "40\r
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document.write( "Please explain. Thank you.
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Algebra.Com's Answer #670091 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 60 could receive FM because they had FM circuitry. \n" ); document.write( "80 could receive AM because they have AM circuitry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you add 60 and 80, you get 140. \n" ); document.write( "since there are only 110 radios, then some of the radios had to have both.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in order to get from 140 to 110, you have to subtract 30.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that is the number of radios that had both.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "how does this work?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are given that 60 had FM circuitry. \n" ); document.write( "if 30 of those also had AM circuitry, then you can break the total down into: \n" ); document.write( "30 had FM circuitry only. \n" ); document.write( "30 had both.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are given that 80 had AM circuitry. \n" ); document.write( "if 30 of those also had FM circuitry, then you can break the total down into: \n" ); document.write( "50 had AM circuitry only. \n" ); document.write( "30 had both.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the ones that had both are being double counted. \n" ); document.write( "they were included in the ones that had AM circuitry and they were included in the ones that had FM circuitry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to remove the double counting, you have to remove the count of one of them.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your total count becomes: \n" ); document.write( "30 had FM only. \n" ); document.write( "50 had AM only. \n" ); document.write( "30 had both.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add that up and you get a total of 110 radios.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the official formula for this phenomenon is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(A or B) = A + B - (A and B).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A would be the set of FM radios. \n" ); document.write( "B would be the set of AM radios.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula of (A or B) = A + B - (A and B) becomes: \n" ); document.write( "(FM or AM) becomes FM + AM - (AM and FM). \n" ); document.write( "replace with the numbers given and you get: \n" ); document.write( "110 = 60 + 80 - (AM and FM). \n" ); document.write( "simplify to get 110 = 140 - (AM and FM). \n" ); document.write( "subtract 110 from both sides of the equation and add (AM and FM) to both sides of the equation to get: \n" ); document.write( "(AM and FM) = 140 - 110. \n" ); document.write( "simplify to get (AM and FM) = 30.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the implied assumption in a problem such as this is that the number of FM radios contains those radios that have both FM and AM circuitry in them.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "likewise, the implied assumption in a problem such as this is that the number of AM radios contains those radios that have both FM and Am circuitry in them.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "as such, the radios that have both FM and AM circuitry in them are being double counted.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is why one set of them has to be subtracted.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the general formula is, once again.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(A or B) = A + B - (A and B)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that the number of elements in set A or set B is equal to the number of elements in set A plus the number of elements in set B minus the number of elements that are in both set A and B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the question was: \n" ); document.write( "How many could receive FM transmission only? \n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "the answer to that would be 30, because. \n" ); document.write( "FM DISABLED_event_only= 30 \n" ); document.write( "AM DISABLED_event_only= 50 \n" ); document.write( "AM and FM combined would be 30.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you may have misstated the problem because 30 isn't one of the selections.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you meant 60 had AM and 80 had FM, then the answer would be 50.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |