document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054890>Question 1054890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is twice as old<BR>\n" );
document.write( "as her daughter now, but ten<BR>\n" );
document.write( "years ago, she was 3 times as old<BR>\n" );
document.write( "as her daughter. Fins their ages<BR>\n" );
document.write( "at present. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670090 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x equal the mother's age now.<BR>\n" );
document.write( "let y equal her daughter's age now.\r<BR>\n" );
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document.write( "the mother is twice as old as the daughter now.<BR>\n" );
document.write( "this means that x = 2y.\r<BR>\n" );
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document.write( "the mother was 3 times as old as her daughter 10 years ago.<BR>\n" );
document.write( "the mother was x - 10 years old ten years ago.<BR>\n" );
document.write( "the daughter was y - 10 years old ten years ago.<BR>\n" );
document.write( "this means that x - 10 = 3 * (y - 10).\r<BR>\n" );
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document.write( "you have two equations that need to be solved simultaneously.<BR>\n" );
document.write( "they are:<BR>\n" );
document.write( "x = 2y<BR>\n" );
document.write( "x - 10 = 3 * (y - 10)\r<BR>\n" );
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document.write( "since x = 2y from the first equation, replace x with 2y in the second equation to get:<BR>\n" );
document.write( "x - 10 = 3 * (y - 10) becomes 2y - 10 = 3 * (y - 10)<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "2y - 10 = 3y - 30<BR>\n" );
document.write( "subtract 2y from both sides of the equation and add 30 to both sides of the eqution to get:<BR>\n" );
document.write( "30 - 10 = 3y - 2y<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "20 = y\r<BR>\n" );
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document.write( "since x = 2y, this means that x = 40.\r<BR>\n" );
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document.write( "you have:<BR>\n" );
document.write( "x = 40<BR>\n" );
document.write( "y = 20\r<BR>\n" );
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document.write( "currently:<BR>\n" );
document.write( "the mother is x years old = 40.<BR>\n" );
document.write( "the daughter is y years old = 20.<BR>\n" );
document.write( "the mother is 2 times as old as the daughter.\r<BR>\n" );
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document.write( "10 years ago:<BR>\n" );
document.write( "the mother was x - 10 = 30 years old.<BR>\n" );
document.write( "the daughter was y - 10 = 10 years old.<BR>\n" );
document.write( "the mother was 3 times as old as the daughter.\r<BR>\n" );
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document.write( "solution looks good.\r<BR>\n" );
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document.write( "solution is:<BR>\n" );
document.write( "mother is currently 40 years old.<BR>\n" );
document.write( "daughter is currently 20 years old.<BR>\n" );
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