document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054834>Question 1054834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of ages of Caroline and Izzy is 19 years old. In three years, 6 times Izzy's age will equal 4 times Caroline's age. How old is each now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670046 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=Caroline<BR>\n" );
document.write( "19-x=Izzy.<BR>\n" );
document.write( "[(19-x)+3]*6=4(x+3)<BR>\n" );
document.write( "(22-x)*6=4x+12<BR>\n" );
document.write( "132-6x=4x+12<BR>\n" );
document.write( "120=10x<BR>\n" );
document.write( "x=12 Caroline is 12<BR>\n" );
document.write( "Izzy is 7<BR>\n" );
document.write( "In 3 years, Caroline will be 15 and Izzy 10.  Six times Izzy's age is 60-4 times Caroline's age.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );