document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054813>Question 1054813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train leaves Orlando at 3:00 pm. a second train leaves the same city in the same direction at 8:00 pm. the second train travels 85 mph faster than the first. if the second train overtakes the first at 11:00 pm, what is the speed of each of the two trains? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670015 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the speed of the first train, and xt=distance at t hours<BR>\n" );
document.write( "(x+85) is the speed of the second train.<BR>\n" );
document.write( "8x=3(x+85), since the first train has traveled for 8 hours by 11 p.m.<BR>\n" );
document.write( "8x=3x+255<BR>\n" );
document.write( "5x=255<BR>\n" );
document.write( "x=51 mph<BR>\n" );
document.write( "x+85=136 mph<BR>\n" );
document.write( "From 3 to 11 is 8 hours or 408 miles at 51 mph<BR>\n" );
document.write( "From 8 to 11 is 3 hours or 408 miles at 136 mph </SPAN>\n" );
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