document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054782>Question 1054782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle and an equilateral have the same perimeter. The length of the rectangle is twice its width. Each side of the triangle is 45m. Find the length of each side of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #670008 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=670008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 45*3= 135 this is the perimeter of the triangle and the rectangle<BR>\n" );
document.write( "L = 2W, thus:<BR>\n" );
document.write( "2(2W)+2W = 135<BR>\n" );
document.write( "4W+2W = 135<BR>\n" );
document.write( "6W = 135<BR>\n" );
document.write( "W = 22.50, and since the length is twice the width:<BR>\n" );
document.write( "L = 22.5*2 = 45<BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2(22.5)+2(45) = 135<BR>\n" );
document.write( "45+90 = 135 Correct<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );