document.write( "Question 1054808: The number of days between billing and payment of charge accounts at Groshen’s, a large department store, is approximately normally distributed with a mean of 18 days and standard deviation of 4 days.\r
\n" );
document.write( "\n" );
document.write( "a.What is the probability that a bill will be paid between 12 and 18 days?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "b.What is the probability that a bill will be paid between 20 and 23 days?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "c.What is the probability that a bill will be paid between 10 and 20 days? \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "d.What is the probability that a bill will take longer than 21 days to be paid? \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "e.What is the probability that a bill will take less than 16 days to be paid?\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #670004 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean of 18 days and standard deviation of 4 days \n" ); document.write( "TI syntax is normalcdf(smaller, larger, µ, σ). \n" ); document.write( "a. P(12 ≤ x ≤ 18)= normalcdf(12,18,18,4) \n" ); document.write( "b. P(20 ≤ x ≤ 23)= normalcdf(20,23,18,4) \n" ); document.write( "c. P(10 ≤ x ≤ 20)= normalcdf(10,20,18,4) \n" ); document.write( "d. P(x > 21) = normalcdf(21,9999,18,4) 9999 a placeholder \n" ); document.write( "e. P(x < 16) = normalcdf(-9999,16,18,4) -9999 a placeholder \n" ); document.write( " |