document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054737>Question 1054737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help<BR>\n" );
document.write( "1. A right angled triangle sides in the ratio 3:5:7. If the hypotenuse is 84mm, find the length of the other two sides.<BR>\n" );
document.write( "2.  A mass is composed of 3 parts of copper and 4 parts of Zinc. Find the mass of copper and Zinc in a casting with a mass of 98kg. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669975 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669975\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. A right angled triangle sides in the ratio 3:5:7. If the hypotenuse is 84mm, find the length of the other two sides.<BR>\n" );
document.write( "This can't be a right triangle, but we can ignore the 7 and find the two sides that has a hypotenuse of 84<BR>\n" );
document.write( "let x = the multiplier<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3x = one side<BR>\n" );
document.write( "5x = the other side<BR>\n" );
document.write( "84 = the hypotenuse<BR>\n" );
document.write( "pythag<BR>\n" );
document.write( "(3x)^2 + (5x)^2 = 84^2<BR>\n" );
document.write( "9x^2 + 25x^2 = 7056<BR>\n" );
document.write( "34x^2 = 7056<BR>\n" );
document.write( "x^2 = 7056/34<BR>\n" );
document.write( "x^2 = 207.53<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28207.53%29 ALIGN=MIDDLE  ALT=\"sqrt%28207.53%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 14.406 is the multiplier<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "3 * 14.406 = 43.218 cm is one side<BR>\n" );
document.write( "and<BR>\n" );
document.write( "5 * 14.406 = 72.030 cm is the other side<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check with your calc: find the hypotenuse: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2843.218%5E2+%2B+72.03%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2843.218%5E2+%2B+72.03%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 84.00<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "2. A mass is composed of 3 parts of copper and 4 parts of Zinc.<BR>\n" );
document.write( " Find the mass of copper and Zinc in a casting with a mass of 98kg.<BR>\n" );
document.write( "Let x = the multiplier<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3x = amt of copper<BR>\n" );
document.write( "4x = amt of zinc<BR>\n" );
document.write( "the equation<BR>\n" );
document.write( "3x + 4x = 98<BR>\n" );
document.write( "7x = 98<BR>\n" );
document.write( "x = 98/7<BR>\n" );
document.write( "x = 14 is the multiplier<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "3 * 14 = 42 kg is the amt of copper<BR>\n" );
document.write( "4 * 14 = 56 kg is the amt of zinc<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check 42 + 56 = 98 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );