document.write( "Question 1054756: The perimeter of a rectangle is 27 cm,and its area is 35 square cm.Find the length and then width of the rectangle.
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Algebra.Com's Answer #669958 by stanbon(75887)\"\" \"About 
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The perimeter of a rectangle is 27 cm,and its area is 35 square cm.Find the length and then width of the rectangle.
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\n" ); document.write( "P = 2(L + W)
\n" ); document.write( "L*W = 35
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\n" ); document.write( "L = (P/2)-W
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\n" ); document.write( "Substitute for \"L\" and solve for \"W\":
\n" ); document.write( "[(P/2)-W]W = 35
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\n" ); document.write( "W^2 - (27/2)W +35 = 0
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\n" ); document.write( "W = [(27/2) +- sqrt[13.5^2 - 4*35]]/(2
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\n" ); document.write( "W = [13.5 +- 6.5]
\n" ); document.write( "Width = 7 cm
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\n" ); document.write( "Since L*W = 35, Length = 5 cm
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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