document.write( "Question 1054748: I have 12 coins that total the value of $2.25. If there are only quarters and dimes, how many of each kind are there \n" ); document.write( "
Algebra.Com's Answer #669957 by addingup(3677)![]() ![]() You can put this solution on YOUR website! q+d = 12, q = 12-d we'll use this value for q below \n" ); document.write( "0.25q+0.10d = 2.25 substitute for q \n" ); document.write( "0.25(12-d)+0.10d = 2.25 \n" ); document.write( "3-0.25d+0.10d = 2.25 \n" ); document.write( "-0.15d = -0.75 Divide both sides by 0.15, and remember -/- = + \n" ); document.write( "d = 5 there are 5 dimes and 12-5 = 7 quarters \n" ); document.write( "------------------------------- \n" ); document.write( "check: \n" ); document.write( "5*0.10 = 0.50 \n" ); document.write( "7*0.25 = 1.75 \n" ); document.write( "Total . .2.25 Correct \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " |