document.write( "Question 1054488: A company manufactures both liquid crystal display (LCD) and plasma televisions. The cost of materials for an LCD television is $125, and the cost of materials for a plasma TV is $150. The cost of labor to manufacture one LCD television is $80, and the cost of labor to manufacture one plasma television is $85. How many of each type of television can the manufacturer produce during a week in which $18,000 has been budgeted for materials and $10,750 has been budgeted for labor? \n" ); document.write( "
Algebra.Com's Answer #669914 by Fombitz(32388)\"\" \"About 
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Let \"X\" be the number of LCD sets, \"Y\" the number of plasma sets.
\n" ); document.write( "Material: \"125X%2B150Y%3C=18000\"
\n" ); document.write( "Labor : \"80X%2B85Y%3C=10750\"
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\n" ); document.write( "You don't have a target to aim for.
\n" ); document.write( "Typically you want to achieve the highest profit or make the most number of TVs.
\n" ); document.write( "I'll assume you want to maximize the number of TVs.
\n" ); document.write( "\"P=X%2BY\"
\n" ); document.write( "So at each of the vertices, calculate P.
\n" ); document.write( "(0,120): \"P=0%2B120=120\"
\n" ); document.write( "(60,70):\"P=60%2B70=130\"
\n" ); document.write( "(134.375,0):\"P=134.375%2B0=134.375\"
\n" ); document.write( "Since you can only make whole TVs, round down to \"P=134\".
\n" ); document.write( "So make only plasma TVs to maximize the number of TVs you make.
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