document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13285>Question 13285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In one day, Machine A caps twice as many bottles as machine B <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+2B ALIGN=MIDDLE  ALT=\"A+=+2B\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Machine C caps 500 more bottles than Machine A <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C+=+A+%2B+500 ALIGN=MIDDLE  ALT=\"C+=+A+%2B+500\"   DISABLED_style= \"max-width:90%; height:auto;\" >. the three machines cap a total of 40,000 bottles in a day <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+%2B+B+%2B+C+=+40000 ALIGN=MIDDLE  ALT=\"A+%2B+B+%2B+C+=+40000\"   DISABLED_style= \"max-width:90%; height:auto;\" >. How many bottles does each of the machines cap in one day? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6699 by </B><A HREF=/tutors/aboutme.mpl?userid=akmb1215><B>akmb1215(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=akmb1215><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have added the equations to your question.  The three equations you have to work with are <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+2B ALIGN=MIDDLE  ALT=\"A+=+2B\"   DISABLED_style= \"max-width:90%; height:auto;\" >....<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C+=+A+%2B+500 ALIGN=MIDDLE  ALT=\"C+=+A+%2B+500\"   DISABLED_style= \"max-width:90%; height:auto;\" >...and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+%2B+B+%2B+C+=+40000 ALIGN=MIDDLE  ALT=\"A+%2B+B+%2B+C+=+40000\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  To solve, you first need to solve A=2B for B so that you can plug it into the last equation.  Once you do this, you get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B=%281%2F2%29A ALIGN=MIDDLE  ALT=\"B=%281%2F2%29A\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which is the same as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B=.5A ALIGN=MIDDLE  ALT=\"B=.5A\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now you can plug this and the other equation in to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+%2B+.5A+%2B+A+%2B+500+=+40000 ALIGN=MIDDLE  ALT=\"A+%2B+.5A+%2B+A+%2B+500+=+40000\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Combine like terms to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.5A+%2B+500+=+40000 ALIGN=MIDDLE  ALT=\"2.5A+%2B+500+=+40000\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Solve to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.5A+=+35000 ALIGN=MIDDLE  ALT=\"2.5A+=+35000\"   DISABLED_style= \"max-width:90%; height:auto;\" > and then finally <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+14000 ALIGN=MIDDLE  ALT=\"A+=+14000\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  To get B and C, simply plug in A to the original equations:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=14000+=+2B ALIGN=MIDDLE  ALT=\"14000+=+2B\"   DISABLED_style= \"max-width:90%; height:auto;\" >....B = 7000.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C+=+14000+%2B+500 ALIGN=MIDDLE  ALT=\"C+=+14000+%2B+500\"   DISABLED_style= \"max-width:90%; height:auto;\" >....C = 14500. </SPAN>\n" );
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