document.write( "Question 13288: With the major options package and destination charge, a sports car cost $24,416. The base price of the car was ten times the price of thr major options package and fifty times the destination charge. What was the base price of the car? \n" ); document.write( "

Algebra.Com's Answer #6698 by akmb1215(68) $\"\"$ $\"About$

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Since the car costs $24,416 with everything, you know that is the base price (B) added to the major options package (M) price and the destination charge (D). This equation can be written as $\"B%2BM%2BD+=+24416\"$ . Your other equations can be written as $\"B+=+10M\"$ and $\"B+=+50D\"$ .\r
\n" ); document.write( "\n" ); document.write( "To solve, you need to first solve the last two equations for M and D. These change to $\"%281%2F10%29B+=+M\"$ and $\"%281%2F50%29B+=+D\"$ . This will be easier if you change those fractions to decimals, to get $\".1B+=+M\"$ and $\".02B+=+D\"$ . Now you can plug these into the first original equation to change it to $\"B+%2B+.1B+%2B+.02B+=+24416\"$ . Combine like terms to get $\"1.12B+=+24416\"$ . Solve by dividing, to get B = 21,800. This is the base price for the car. \n" ); document.write( "

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