document.write( "Question 1054618: On a map the scale is 1 inches=50 miles.If the distance on the map is 4 inches, find the actual distance\r
\n" ); document.write( "\n" ); document.write( "I really don't understand this please help\r
\n" ); document.write( "\n" ); document.write( "Sincerely,
\n" ); document.write( " Alex
\n" ); document.write( "

Algebra.Com's Answer #669799 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The \"scale' of a map is the shrinking factor
\n" ); document.write( "that the actual size things are shrunk down to
\n" ); document.write( "The factor for this map is \"+1%2F50+\" in/mi
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "In terms of just units:
\n" ); document.write( "[ inches on the map ] = [ inches / mile ]x[ real world miles ]
\n" ); document.write( "Plug in the given data:
\n" ); document.write( "\"+4+=+%28+1%2F50+%29%2Ad+\"
\n" ); document.write( "where \"+d+\" = the actual distance in miles
\n" ); document.write( "Multiply both sides by \"+50+\"
\n" ); document.write( "\"+200+=+d+\"
\n" ); document.write( "200 mi is the actual distance
\n" ); document.write( "
\n" ); document.write( "
\n" );