document.write( "Question 1054600: Marge left her home in Springfield at 9:00 A.M. and drove to Shelbyville, arriving at 10:45 A.M.
\n" ); document.write( "She went shopping at the Shelbyville Galleria and had lunch at Krusty Burger in the food court. She
\n" ); document.write( "left to return home at 2:15 P.M. Because it had started raining, she drove 10 mph slower than she
\n" ); document.write( "did that morning. Marge got home at 4:15 P.M. What is the distance between the two cities?
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Algebra.Com's Answer #669786 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Her driving time to Shelbyville was
\n" ); document.write( "10:45 minus 9:00 = \"+1.75+\" hrs
\n" ); document.write( "( I converted 45 min to \"+.75+\" hrs )
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\n" ); document.write( "Her driving time back to Springfield was
\n" ); document.write( "4:15 minus 2:15 = \"+2+\" hrs
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\n" ); document.write( "Let \"+s+\" = her speed in mi/hr
\n" ); document.write( "driving to Shelbyville
\n" ); document.write( "\"+s+-+10+\" = her speed driving back
\n" ); document.write( "to Springfield in mi/hr
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\n" ); document.write( "Let \"+d+\" = the distance between
\n" ); document.write( "the two cities in miles
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\n" ); document.write( "Equation for drive to Shelbyville:
\n" ); document.write( "(1) \"+d+=+s%2A1.75+\"
\n" ); document.write( "Equation for drive back to Springfield:
\n" ); document.write( "(2) \"+d+=+%28+s+-+10+%29%2A2+\"
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\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+1.75s+=+2%2A%28+s+-+10+%29+\"
\n" ); document.write( "(2) \"+1.75s+=+2s+-+20+\"
\n" ); document.write( "(2) \"+.25s+=+20+\"
\n" ); document.write( "(2) \"+s+=+80+\"
\n" ); document.write( "--------------------
\n" ); document.write( "(1) \"+d+=+1.75s+\"
\n" ); document.write( "(1) \"+d+=+1.75%2A80+\"
\n" ); document.write( "(1) \"+d+=+140+\"
\n" ); document.write( "the distance between the 2 cities is 140 mi
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\n" ); document.write( "check answer:
\n" ); document.write( "(2) \"+d+=+%28+s+-+10+%29%2A2+\"
\n" ); document.write( "(2) \"+d+=+%28+80+-+10+%29%2A2+\"
\n" ); document.write( "(2) \"+d+=+2%2A70+\"
\n" ); document.write( "(2) \"+d+=+140+\"
\n" ); document.write( "OK
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