document.write( "Question 1054563: Solve the following exponential equation:\r
\n" ); document.write( "\n" ); document.write( "4^(1-3x) = 5^(0.5x+7)\r
\n" ); document.write( "\n" ); document.write( "I have it about half way and then I'm stuck, really need to see all the steps. Thank you.
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Algebra.Com's Answer #669775 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Take log of both sides and change one of them using Change of Base formula.\r
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\n" ); document.write( "\n" ); document.write( "Another way is just use log base ten.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C4%5E%281-3x%29%29=log%2810%2C5%5E%280.5x%2B7%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281-3x%29%2Alog%28%284%29%29=%280.5x%2B7%29log%28%285%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%284%29%29-3%2Alog%28%284%29%29x=0.5%2Alog%28%285%29%29x%2B7%2Alog%28%285%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%284%29%29=0.5%2Alog%28%285%29%29x%2B3%2Alog%28%284%29%29%2B7%2Alog%28%285%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%284%29%29-7%2Alog%28%285%29%29=x%280.5%2Alog%28%285%29%29%2B3%2Alog%28%284%29%29%29\"\r
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\n" ); document.write( "Look in your reference information for those logarithms, base ten, and do the computations for x.
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