document.write( "Question 1054552: Find the exact solution of the exponential equation in terms of logarithms:
\n" ); document.write( "4^x + 2^1+2x = 40\r
\n" ); document.write( "\n" ); document.write( "Simplified answer, should contain natural logarithms
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Algebra.Com's Answer #669764 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"4%5Ex+%2B+2%5E%281%2B2x%29+=+40\"
\n" ); document.write( "\"%282%5E2%29%5Ex+%2B+2%5E%281%2B2x%29+=+40\"
\n" ); document.write( "\"2%5E%282x%29%2B2%5E1%2A2%5E%282x%29=40\"
\n" ); document.write( "\"2%5E%282x%29%281%2B2%29=40\"
\n" ); document.write( "\"2%5E%282x%29=40%2F3\"
\n" ); document.write( "\"2x=log%282%2C%2840%2F3%29%29\"
\n" ); document.write( "\"x=%281%2F2%29log%282%2C%2840%2F3%29%29\"
\n" ); document.write( "\"x=%281%2F2%29%28log%28%2840%2F3%29%29%2Flog%28%282%29%29%29\"\r
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