document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1054540>Question 1054540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of A and B is 30 years and 5 years hence A will be three times as old as B. Find their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #669743 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=669743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of A and B is 30 years and 5 years hence A will be three times as old as B. Find their ages. <BR>\n" );
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document.write( "A + B = 30<BR>\n" );
document.write( "A+5 = 3(B+5)<BR>\n" );
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document.write( "Substitute for \"A\" and solve for \"B\"::<BR>\n" );
document.write( "30-B + 5 = 3B+15<BR>\n" );
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document.write( "4B = 20<BR>\n" );
document.write( "B = 5 yrs<BR>\n" );
document.write( "A = 25 yrs<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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